14x^2+5-[7x(x^2-2)+4]=0

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Solution for 14x^2+5-[7x(x^2-2)+4]=0 equation: 


Simplifying
14x2 + 5 + -1[7x(x2 + -2) + 4] = 0

Reorder the terms:
14x2 + 5 + -1[7x(-2 + x2) + 4] = 0
14x2 + 5 + -1[(-2 * 7x + x2 * 7x) + 4] = 0
14x2 + 5 + -1[(-14x + 7x3) + 4] = 0

Reorder the terms:
14x2 + 5 + -1[4 + -14x + 7x3] = 0
14x2 + 5 + [4 * -1 + -14x * -1 + 7x3 * -1] = 0
14x2 + 5 + [-4 + 14x + -7x3] = 0

Reorder the terms:
5 + -4 + 14x + 14x2 + -7x3 = 0

Combine like terms: 5 + -4 = 1
1 + 14x + 14x2 + -7x3 = 0

Solving
1 + 14x + 14x2 + -7x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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